Perl Subroutines
by Geethalakshmi[ Edit ] 2010-09-17 12:43:11
Perl Subroutines
A subroutine may be declared as follows:
sub NAME BLOCK
Any arguments passed to the routine come in as array `@_', that is `($_[0], $_[1], ...)'. The array `@_' is a local array, but its values are references to the actual scalar parameters. The return value of the subroutine is the value of the last expression evaluated, and can be either an array value or a scalar value. Alternately, a return statement may be used to specify the returned value and exit the subroutine. To create local variables see the local operator.
A subroutine is called using the do operator or the & operator.
Example:
sub MAX {
local($max) = pop(@_);
foreach $foo (@_) {
$max = $foo if $max < $foo;
}
$max;
}
...
$bestday = &MAX($mon,$tue,$wed,$thu,$fri);
Example:
# get a line, combining continuation lines
# that start with whitespace
sub get_line {
$thisline = $lookahead;
line: while ($lookahead =
) {
if ($lookahead =~ /^[ \t]/) {
$thisline .= $lookahead;
}
else {
last line;
}
}
$thisline;
}
$lookahead = ; # get first line
while ($_ = do get_line()) {
...
}
Use array assignment to a local list to name your formal arguments:
sub maybeset {
local($key, $value) = @_;
$foo{$key} = $value unless $foo{$key};
}
This also has the effect of turning call-by-reference into call-by-value, since the assignment copies the values.
Subroutines may be called recursively. If a subroutine is called using the `&' form, the argument list is optional. If omitted, no `@_' array is set up for the subroutine; the `@_' array at the time of the call is visible to subroutine instead.
do foo(1,2,3); # pass three arguments
&foo(1,2,3); # the same
do foo(); # pass a null list
&foo(); # the same
&foo; # pass no arguments--more efficient