All numbers are equal

by Nirmala 2010-09-18 17:05:57

All numbers are equal
Theorem: All numbers are equal.
Proof: Choose arbitrary a and b, and let t = a + b. Then


a + b = t
(a + b)(a - b) = t(a - b)
a^2 - b^2 = ta - tb
a^2 - ta = b^2 - tb
a^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4
(a - t/2)^2 = (b - t/2)^2
a - t/2 = b - t/2
a = b


So all numbers are the same, and math is pointless.

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