Vedic Maths Multiplication
by Francis[ Edit ] 2013-05-14 11:27:55
Vedic Maths Multiplication by 9's Third Method
Last two method are very easy to remember. (http://hiox.org/36967-vedic-maths-multiply-by-9's.php) But its little difficult, if you have more practice its also simple one.
Type III : Multiplicand greater than Multiplier
Step 1 : Count number of digit in Multiplier (n)
Step 2 : Remove step 1 n digit in Multiplicand and assign as A
Step 3 : add 1 from step 2 result
Step 4 : Step 2 Removed value subtract by Step 3 value and assign as B
Step 5 : Step 4 result is negative value, Step 2 Removed value before append one and subtract by Step 3 value and Assign as B. And also A value subtract by 1 and assign as A.
Step 6 : Find complement Step 2 Removed value. And assign as C
Step 7 : Append all value ABC (its final answer).
Example 1 : 456 * 99
Step 1 : n = 2
Step 2 : A = 4 (removed value is 56)
Step 3 : 4 + 1 = 5
Step 4 : B = 56 - 5 = 51 (B)
Step 5 : 51 is not negative value (omit this step)
Step 6 : complement of 56 is 44 (C)
Step 7 : ABC = 45144 (Its Final Answer)
Example 2 : 3821 * 99
Step 1 : n = 2
Step 2 : A = 38 (removed value is 21)
Step 3 : 38 + 1 = 39
Step 4 : B = 21 - 39 = -18 (B)
Step 5 : -18 is negative value. So, 121 - 39 = 82 (B) and also 38 - 1 = 37 (A)
Step 6 : complement of 21 is 79 (C)
Step 7 : ABC = 378279 (Its Final Answer)
