Multiplication of except last dight mulitplier must have ones trick - Vedic Maths
by Francis[ Edit ] 2013-07-03 13:47:42
Multiplication of except last dight mulitplier must have ones trick - Vedic Maths
Conditions:
1) Take any number as a multiplicand.
2) Multiplier must have ones except last digit.
Rules:
Rule 1 : Multiplier last digit assign as X.
Rule 2 : Count number of digits of multiplier assign as N.
Rule 3 : Putting N-1 dots on both the sides. Dot value consider as a zero.
Rule 4 : Start from RHS dot, taking N digits at a time. X multiply by the Nth last digit is added to the sum of all other digits. If you have carry value, carry the next N digits.
Rule 5 : Write answer in reverse order.
Example: 321 X 1114
Rule 1 : X = 4
Rule 2 : N = 4
Rule 3 : ...321...
Rule 4 : Take 3 dots and 1, (4x1) + 0 + 0 + 0 =
4
Take next 4 digits, 2 dots, 1 and 2, (4x2) + 1 + 0 + 0 =
9
Take next 4 digits, dot, 1, 2 and 3, (4x3) + 2 + 1 + 0 = 15 =
5 (carry 1)
Take next 4 digits, 1, 2, 3 and dot, (4x0) + 3 + 2 + 1 + 1 (carry) =
7
Take next 4 digits, 2, 3 and 2 dots, (4x0) + 0 + 3 + 2 =
5
Take next 4 digits, 3 and 3 dots, (4x0) + 0 + 0 + 3 =
3
Rule 5 : Write answer in backwards,
321 X 1114 = 357594
